-3x^2-18x-22=0

Solution for -3x^2-18x-22=0 equation:

-3x^2-18x-22=0

a = -3; b = -18; c = -22;
Δ = b2-4ac
Δ = -182-4·(-3)·(-22)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{15}}{2*-3}=\frac{18-2\sqrt{15}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{15}}{2*-3}=\frac{18+2\sqrt{15}}{-6}
$